Integrand size = 40, antiderivative size = 127 \[ \int \frac {\tan ^2(c+d x) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right )}{a+b \tan (c+d x)} \, dx=-\frac {(b B-a C) x}{a^2+b^2}+\frac {(a B+b C) \log (\cos (c+d x))}{\left (a^2+b^2\right ) d}-\frac {a^3 (b B-a C) \log (a+b \tan (c+d x))}{b^3 \left (a^2+b^2\right ) d}+\frac {(b B-a C) \tan (c+d x)}{b^2 d}+\frac {C \tan ^2(c+d x)}{2 b d} \]
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Time = 0.57 (sec) , antiderivative size = 127, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.175, Rules used = {3713, 3688, 3728, 3707, 3698, 31, 3556} \[ \int \frac {\tan ^2(c+d x) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right )}{a+b \tan (c+d x)} \, dx=\frac {(a B+b C) \log (\cos (c+d x))}{d \left (a^2+b^2\right )}-\frac {x (b B-a C)}{a^2+b^2}-\frac {a^3 (b B-a C) \log (a+b \tan (c+d x))}{b^3 d \left (a^2+b^2\right )}+\frac {(b B-a C) \tan (c+d x)}{b^2 d}+\frac {C \tan ^2(c+d x)}{2 b d} \]
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Rule 31
Rule 3556
Rule 3688
Rule 3698
Rule 3707
Rule 3713
Rule 3728
Rubi steps \begin{align*} \text {integral}& = \int \frac {\tan ^3(c+d x) (B+C \tan (c+d x))}{a+b \tan (c+d x)} \, dx \\ & = \frac {C \tan ^2(c+d x)}{2 b d}+\frac {\int \frac {\tan (c+d x) \left (-2 a C-2 b C \tan (c+d x)+2 (b B-a C) \tan ^2(c+d x)\right )}{a+b \tan (c+d x)} \, dx}{2 b} \\ & = \frac {(b B-a C) \tan (c+d x)}{b^2 d}+\frac {C \tan ^2(c+d x)}{2 b d}+\frac {\int \frac {-2 a (b B-a C)-2 b^2 B \tan (c+d x)-2 \left (a b B-a^2 C+b^2 C\right ) \tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx}{2 b^2} \\ & = -\frac {(b B-a C) x}{a^2+b^2}+\frac {(b B-a C) \tan (c+d x)}{b^2 d}+\frac {C \tan ^2(c+d x)}{2 b d}-\frac {\left (a^3 (b B-a C)\right ) \int \frac {1+\tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx}{b^2 \left (a^2+b^2\right )}-\frac {(a B+b C) \int \tan (c+d x) \, dx}{a^2+b^2} \\ & = -\frac {(b B-a C) x}{a^2+b^2}+\frac {(a B+b C) \log (\cos (c+d x))}{\left (a^2+b^2\right ) d}+\frac {(b B-a C) \tan (c+d x)}{b^2 d}+\frac {C \tan ^2(c+d x)}{2 b d}-\frac {\left (a^3 (b B-a C)\right ) \text {Subst}\left (\int \frac {1}{a+x} \, dx,x,b \tan (c+d x)\right )}{b^3 \left (a^2+b^2\right ) d} \\ & = -\frac {(b B-a C) x}{a^2+b^2}+\frac {(a B+b C) \log (\cos (c+d x))}{\left (a^2+b^2\right ) d}-\frac {a^3 (b B-a C) \log (a+b \tan (c+d x))}{b^3 \left (a^2+b^2\right ) d}+\frac {(b B-a C) \tan (c+d x)}{b^2 d}+\frac {C \tan ^2(c+d x)}{2 b d} \\ \end{align*}
Result contains complex when optimal does not.
Time = 1.58 (sec) , antiderivative size = 138, normalized size of antiderivative = 1.09 \[ \int \frac {\tan ^2(c+d x) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right )}{a+b \tan (c+d x)} \, dx=\frac {-\frac {b (B+i C) \log (i-\tan (c+d x))}{a+i b}-\frac {b (B-i C) \log (i+\tan (c+d x))}{a-i b}+\frac {2 a^3 (-b B+a C) \log (a+b \tan (c+d x))}{b^2 \left (a^2+b^2\right )}+\frac {2 (b B-a C) \tan (c+d x)}{b}+C \tan ^2(c+d x)}{2 b d} \]
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Time = 0.12 (sec) , antiderivative size = 127, normalized size of antiderivative = 1.00
method | result | size |
derivativedivides | \(\frac {\frac {\frac {C \tan \left (d x +c \right )^{2} b}{2}+B \tan \left (d x +c \right ) b -C \tan \left (d x +c \right ) a}{b^{2}}+\frac {\frac {\left (-B a -C b \right ) \ln \left (1+\tan \left (d x +c \right )^{2}\right )}{2}+\left (-B b +C a \right ) \arctan \left (\tan \left (d x +c \right )\right )}{a^{2}+b^{2}}-\frac {a^{3} \left (B b -C a \right ) \ln \left (a +b \tan \left (d x +c \right )\right )}{b^{3} \left (a^{2}+b^{2}\right )}}{d}\) | \(127\) |
default | \(\frac {\frac {\frac {C \tan \left (d x +c \right )^{2} b}{2}+B \tan \left (d x +c \right ) b -C \tan \left (d x +c \right ) a}{b^{2}}+\frac {\frac {\left (-B a -C b \right ) \ln \left (1+\tan \left (d x +c \right )^{2}\right )}{2}+\left (-B b +C a \right ) \arctan \left (\tan \left (d x +c \right )\right )}{a^{2}+b^{2}}-\frac {a^{3} \left (B b -C a \right ) \ln \left (a +b \tan \left (d x +c \right )\right )}{b^{3} \left (a^{2}+b^{2}\right )}}{d}\) | \(127\) |
norman | \(\frac {\left (B b -C a \right ) \tan \left (d x +c \right )}{b^{2} d}-\frac {\left (B b -C a \right ) x}{a^{2}+b^{2}}+\frac {C \tan \left (d x +c \right )^{2}}{2 b d}-\frac {\left (B a +C b \right ) \ln \left (1+\tan \left (d x +c \right )^{2}\right )}{2 d \left (a^{2}+b^{2}\right )}-\frac {a^{3} \left (B b -C a \right ) \ln \left (a +b \tan \left (d x +c \right )\right )}{b^{3} \left (a^{2}+b^{2}\right ) d}\) | \(131\) |
parallelrisch | \(-\frac {2 B x \,b^{4} d -2 C x a \,b^{3} d -C \tan \left (d x +c \right )^{2} a^{2} b^{2}-C \tan \left (d x +c \right )^{2} b^{4}+B \ln \left (1+\tan \left (d x +c \right )^{2}\right ) a \,b^{3}+2 B \ln \left (a +b \tan \left (d x +c \right )\right ) a^{3} b -2 B \tan \left (d x +c \right ) a^{2} b^{2}-2 B \tan \left (d x +c \right ) b^{4}+C \ln \left (1+\tan \left (d x +c \right )^{2}\right ) b^{4}-2 C \ln \left (a +b \tan \left (d x +c \right )\right ) a^{4}+2 C \tan \left (d x +c \right ) a^{3} b +2 C \tan \left (d x +c \right ) a \,b^{3}}{2 \left (a^{2}+b^{2}\right ) b^{3} d}\) | \(188\) |
risch | \(\frac {2 i C \,a^{2} c}{b^{3} d}-\frac {x C}{i b -a}-\frac {2 i B a c}{b^{2} d}-\frac {2 i C c}{b d}-\frac {2 i C x}{b}-\frac {2 i B a x}{b^{2}}-\frac {i x B}{i b -a}-\frac {2 i a^{4} C x}{\left (a^{2}+b^{2}\right ) b^{3}}+\frac {2 i C \,a^{2} x}{b^{3}}+\frac {2 i a^{3} B c}{\left (a^{2}+b^{2}\right ) b^{2} d}-\frac {2 i a^{4} C c}{\left (a^{2}+b^{2}\right ) b^{3} d}+\frac {2 i a^{3} B x}{\left (a^{2}+b^{2}\right ) b^{2}}+\frac {2 i \left (-i C b \,{\mathrm e}^{2 i \left (d x +c \right )}+B b \,{\mathrm e}^{2 i \left (d x +c \right )}-C a \,{\mathrm e}^{2 i \left (d x +c \right )}+B b -C a \right )}{b^{2} d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{2}}+\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right ) B a}{b^{2} d}-\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right ) C \,a^{2}}{b^{3} d}+\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right ) C}{b d}-\frac {a^{3} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-\frac {i b +a}{i b -a}\right ) B}{\left (a^{2}+b^{2}\right ) b^{2} d}+\frac {a^{4} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-\frac {i b +a}{i b -a}\right ) C}{\left (a^{2}+b^{2}\right ) b^{3} d}\) | \(415\) |
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Time = 0.27 (sec) , antiderivative size = 190, normalized size of antiderivative = 1.50 \[ \int \frac {\tan ^2(c+d x) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right )}{a+b \tan (c+d x)} \, dx=\frac {2 \, {\left (C a b^{3} - B b^{4}\right )} d x + {\left (C a^{2} b^{2} + C b^{4}\right )} \tan \left (d x + c\right )^{2} + {\left (C a^{4} - B a^{3} b\right )} \log \left (\frac {b^{2} \tan \left (d x + c\right )^{2} + 2 \, a b \tan \left (d x + c\right ) + a^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) - {\left (C a^{4} - B a^{3} b - B a b^{3} - C b^{4}\right )} \log \left (\frac {1}{\tan \left (d x + c\right )^{2} + 1}\right ) - 2 \, {\left (C a^{3} b - B a^{2} b^{2} + C a b^{3} - B b^{4}\right )} \tan \left (d x + c\right )}{2 \, {\left (a^{2} b^{3} + b^{5}\right )} d} \]
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Result contains complex when optimal does not.
Time = 0.93 (sec) , antiderivative size = 1306, normalized size of antiderivative = 10.28 \[ \int \frac {\tan ^2(c+d x) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right )}{a+b \tan (c+d x)} \, dx=\text {Too large to display} \]
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Time = 0.30 (sec) , antiderivative size = 130, normalized size of antiderivative = 1.02 \[ \int \frac {\tan ^2(c+d x) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right )}{a+b \tan (c+d x)} \, dx=\frac {\frac {2 \, {\left (C a - B b\right )} {\left (d x + c\right )}}{a^{2} + b^{2}} + \frac {2 \, {\left (C a^{4} - B a^{3} b\right )} \log \left (b \tan \left (d x + c\right ) + a\right )}{a^{2} b^{3} + b^{5}} - \frac {{\left (B a + C b\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right )}{a^{2} + b^{2}} + \frac {C b \tan \left (d x + c\right )^{2} - 2 \, {\left (C a - B b\right )} \tan \left (d x + c\right )}{b^{2}}}{2 \, d} \]
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Time = 0.65 (sec) , antiderivative size = 135, normalized size of antiderivative = 1.06 \[ \int \frac {\tan ^2(c+d x) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right )}{a+b \tan (c+d x)} \, dx=\frac {\frac {2 \, {\left (C a - B b\right )} {\left (d x + c\right )}}{a^{2} + b^{2}} - \frac {{\left (B a + C b\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right )}{a^{2} + b^{2}} + \frac {2 \, {\left (C a^{4} - B a^{3} b\right )} \log \left ({\left | b \tan \left (d x + c\right ) + a \right |}\right )}{a^{2} b^{3} + b^{5}} + \frac {C b \tan \left (d x + c\right )^{2} - 2 \, C a \tan \left (d x + c\right ) + 2 \, B b \tan \left (d x + c\right )}{b^{2}}}{2 \, d} \]
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Time = 8.20 (sec) , antiderivative size = 144, normalized size of antiderivative = 1.13 \[ \int \frac {\tan ^2(c+d x) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right )}{a+b \tan (c+d x)} \, dx=\frac {\mathrm {tan}\left (c+d\,x\right )\,\left (\frac {B}{b}-\frac {C\,a}{b^2}\right )}{d}-\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )-\mathrm {i}\right )\,\left (-C+B\,1{}\mathrm {i}\right )}{2\,d\,\left (-b+a\,1{}\mathrm {i}\right )}+\frac {\ln \left (a+b\,\mathrm {tan}\left (c+d\,x\right )\right )\,\left (C\,a^4-B\,a^3\,b\right )}{d\,\left (a^2\,b^3+b^5\right )}-\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )\,\left (B-C\,1{}\mathrm {i}\right )}{2\,d\,\left (a-b\,1{}\mathrm {i}\right )}+\frac {C\,{\mathrm {tan}\left (c+d\,x\right )}^2}{2\,b\,d} \]
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